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Text Solution

`e^(2)``a^(2)``b^(2)``b^(2)//a^(2)`

Answer :

BSolution :

<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_CG_C07_E07_034_S01.png" width="80%"> <br> Tangent at point P is <br> `(x)/(a) sec theta-(y)/(b) tan theta=1` <br> It meets the x-axis at T `(a cos theta, 0)` and the foot of perpendicular from P to the x-axis is N `(a sec theta, 0)`. <br> From the diagram, <br> OT = `a cos theta and ON = a sec theta` <br> `therefore" "OT*ON=a^(2)`